-16x^2+43x=0

Solution for -16x^2+43x=0 equation:

-16x^2+43x=0

a = -16; b = 43; c = 0;
Δ = b2-4ac
Δ = 432-4·(-16)·0
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-43}{2*-16}=\frac{-86}{-32}
=2+11/16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+43}{2*-16}=\frac{0}{-32}
=0
$